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FIS01069
Introdução_a_computacao_UFPB
Commits
a0f179e7
Commit
a0f179e7
authored
Oct 31, 2014
by
Eduardo de Santana Medeiros Alexandre
Browse files
Atualização das imagens do cap3 #22
parent
084c016c
Changes
53
Hide whitespace changes
Inline
Side-by-side
livro/capitulos/cap3-sistema-de-numeracao.asc
View file @
a0f179e7
...
...
@@ -61,7 +61,7 @@ nesse sistema de numeração.
[[sistema_egipcio]]
.Sistema de Numeração Egípcio
image::images/
sistema-de-numeracao
/sistema_egipicio.
png
[scaledwidth="70%"]
image::images/
{cap}
/sistema_egipicio.
eps
[scaledwidth="70%"]
Este sistema adota o princípio aditivo, ou seja, os símbolos possuem seus
...
...
@@ -80,16 +80,16 @@ números, de 7 a 59, nesse sistema de numeração.
[[fig_sistema_babilonico]]
.Sistema de Numeração Babilônico
image::images/
sistema-de-numeracao
/sistema_babilonico.
png
[scaledwidth="70%"]
image::images/
{cap}
/sistema_babilonico.
eps
[scaledwidth="70%"]
[NOTE]
==================
Agora é com você. Qual seria o valor que cada símbolo babilônico, seguindo
os exemplos da <<fig_sistema_babilonico>>?
image:images/
sistema-de-numeracao
/um_babilonico.
png
[] = ?
image:images/
{cap}
/um_babilonico.
eps
[] = ?
image:images/
sistema-de-numeracao
/dez_babilonico.
png
[] = ?
image:images/
{cap}
/dez_babilonico.
eps
[] = ?
==================
==== Sistema de numeração Romano
...
...
@@ -116,7 +116,7 @@ máximo, três vezes.
[[sistema_romano]]
.Sistema de Numeração Romano
image::images/
sistema-de-numeracao
/sistema_romano.
png
[scaledwidth="60%"]
image::images/
{cap}
/sistema_romano.
eps
[scaledwidth="60%"]
==== Sistema de numeração Indo-Arábico
...
...
@@ -149,7 +149,7 @@ indo-arábicos, ao longo do tempo.
[[fig_sistema_indo_arabico]]
.Sistema de numeração Indo-Arábico
image::images/
sistema-de-numeracao
/sistema_arabico.
png
[scaledwidth="70%"]
image::images/
{cap}
/sistema_arabico.
eps
[scaledwidth="70%"]
Observe que, inicialmente, os hindus não utilizavam o zero. A criação de um
símbolo para o *nada*, ou seja, o zero, foi uma das grandes invenções dos
...
...
@@ -409,7 +409,7 @@ divisão (que resulta em quociente 0) ocupe a posição de mais alta ordem.
- Conversão do número 19~10~ para a base 2:
image::images/
sistema-de-numeracao
/conversao-fazendo-divisao.
png
[scaledwidth="70%", width="50%"]
image::images/
{cap}
/conversao-fazendo-divisao.
eps
[scaledwidth="70%", width="50%"]
Logo temos:
...
...
@@ -428,7 +428,7 @@ ____
Conversão do número 278~10~ para a base 16:
image::images/
sistema-de-numeracao
/278_16.
png
[scaledwidth="50%", width="50%"]
image::images/
{cap}
/278_16.
eps
[scaledwidth="50%", width="50%"]
Logo temos:
...
...
@@ -465,7 +465,7 @@ NOTE: Soma-se as posições da direita para esquerda, tal como uma soma decimal.
Solução:
image::images/
sistema-de-numeracao
/figura1.
png
[scaledwidth="40%"]
image::images/
{cap}
/figura1.
eps
[scaledwidth="40%"]
A tabuada da subtração aritmética binária:
...
...
@@ -483,7 +483,7 @@ Por exemplo: 11100~2~ – 01010~2~ = ?
Solução:
image::images/
sistema-de-numeracao
/figura2.
png
[scaledwidth="25%"]
image::images/
{cap}
/figura2.
eps
[scaledwidth="25%"]
NOTE: Não esqueça, subtrai-se as colunas da direita para a esquerda, tal como
uma subtração decimal.
...
...
@@ -523,7 +523,7 @@ Efetuar: 101~2~ x 110~2~
Solução:
image::images/
sistema-de-numeracao
/figura5.
png
[scaledwidth="40%"]
image::images/
{cap}
/figura5.
eps
[scaledwidth="40%"]
No entanto, a multiplicação em computadores é feita, também, por um
artifício: para multiplicar A por n somamos A com A (n-1) vezes.
...
...
@@ -579,7 +579,7 @@ Como o próprio nome indica, a representação *sinal* e *amplitude* é dividida
para representar o sinal, o bit mais à esquerda: *0* para indicar um valor
positivo, *1* para indicar um valor negativo. Já o resto dos bits representam seu valor absoluto.
image::images/
sistema-de-numeracao
/sinal_magnitude.
png
[scaledwidth="40%", width="50%"]
image::images/
{cap}
/sinal_magnitude.
eps
[scaledwidth="40%", width="50%"]
==== Complemento de 1
...
...
@@ -680,7 +680,7 @@ Uma característica do sistema de complemento de dois é que tanto os números
com sinal quanto os números sem sinal podem ser somados pelo mesmo circuito.
Por exemplo, suponha que você deseja somar os números sem sinal 132~10~ e 14~10~.
image::images/
sistema-de-numeracao
/figura3.
png
[scaledwidth="60%"]
image::images/
{cap}
/figura3.
eps
[scaledwidth="60%"]
O microprocessador tem um circuito na ULA (Unidade Lógica e
Aritmética) que pode somar números binários sem sinal, quando aparece o
...
...
@@ -693,7 +693,7 @@ resposta é: não sabe. A ULA sempre soma como se as entradas fossem números
binários sem sinal. Sempre produzirá o resultado correto, mesmo se as
entradas forem números em complemento de dois.
image::images/
sistema-de-numeracao
/figura4.
png
[scaledwidth="60%"]
image::images/
{cap}
/figura4.
eps
[scaledwidth="60%"]
Isto comprova um ponto muito importante. O somador na ULA sempre soma padrões
de bits como se eles fossem números binários sem sinal. É a nossa
...
...
@@ -720,7 +720,7 @@ Como exemplo temos a subtração de 69~10~ (Minuendo) por 26~10~ (Subtraendo).
Jogue fora o transporte final:
image::images/
sistema-de-numeracao
/transporte-final.
png
[scaledwidth="100%"]
image::images/
{cap}
/transporte-final.
eps
[scaledwidth="100%"]
[NOTE]
====
...
...
@@ -747,7 +747,7 @@ decrementada em 1 a cada casa afastada do ponto.
Exemplo:
.Representação de ponto fixo
image::images/
sistema-de-numeracao
/ponto-fixo.
png
[]
image::images/
{cap}
/ponto-fixo.
eps
[]
==== Soma e subtração de números fracionários
...
...
@@ -757,7 +757,7 @@ subtração binária demonstrada anteriormente.
Exemplos:
image::images/
sistema-de-numeracao
/figura6.
png
[scaledwidth="50%"]
image::images/
{cap}
/figura6.
eps
[scaledwidth="50%"]
=== Fundamentos da Notação de Ponto Flutuante
...
...
@@ -862,7 +862,7 @@ e o campo da mantissa, como mostrado na <<fig_sinal_expoente_mantissa>>.
[[fig_sinal_expoente_mantissa]]
.Divisão de 1 byte nos campos da Notação de Ponto Flutuante
image::images/
sistema-de-numeracao
/sinal_expoente_mantissa.
png
[scaledwidth="60%"]
image::images/
{cap}
/sinal_expoente_mantissa.
eps
[scaledwidth="60%"]
...
...
@@ -927,7 +927,7 @@ os bits de sinal forem iguais a ‘0’, o maior dos dois valores é aquele que
apresentar, da esquerda para a direita, um ‘1’ no bit em que os padrões
diferem, logo ao comparar:
image::images/
sistema-de-numeracao
/figura7.
png
[scaledwidth="40%"]
image::images/
{cap}
/figura7.
eps
[scaledwidth="40%"]
Conclui-se que o primeiro padrão é maior que o segundo, sem haver a
necessidade de decodificar as representações em Ponto Flutuante, tarefa que
...
...
@@ -957,7 +957,7 @@ parcela: 0,125) se perde, como pode ser observado na figura abaixo:
Logo temos:
image::images/
sistema-de-numeracao
/bit_perdido.
png
[]
image::images/
{cap}
/bit_perdido.
eps
[]
Ao ignorarmos este problema, e continuarmos a preencher o campo do expoente e
do bit do sinal, teremos o padrão de bits 01101010, que representa o valor 2,5
...
...
@@ -1006,7 +1006,7 @@ Processo:
Equalizando os expoentes, temos:
image::images/
sistema-de-numeracao
/figura8.
png
[]
image::images/
{cap}
/figura8.
eps
[]
Normalizando:
...
...
livro/images/cap3/278_16.eps
0 → 100644
View file @
a0f179e7
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